A builder is pricing a single-storey frame and needs the stud count, plate lineal metres and nogging count for a 6.0m x 2.7m wall with one door opening before the timber order goes in.
US (stick frame): 2×4 or 2×6 lumber at 16" or 24" on-centre. Fire blocking required at mid-height per IRC.
Double top plate is standard in both AU and US. Corner studs require 3 studs (AU) or king/jack configuration (US).
Add 10–15% to stud count for waste, cutting and corners.
1 What this calculator does
Calculates the number of studs, lineal metres of plate timber, nogging count and approximate lineal metres of noggings for a timber-framed wall. Inputs are wall length, wall height, stud spacing, number of openings and number of nogging rows. Supports metric and imperial.
2 Formula & professional reasoning
Studs from spacing = Ceiling(Wall length / Spacing) + 1
Extra studs = Openings x 2 (king studs) + 2 (corners/ends)
Total studs = Studs from spacing + Extra studs
Stud length = Wall height - (2 x plate thickness 45mm)
Plate lineal metres = Wall length x 3 (double top + bottom)
Noggings = (Studs from spacing - 1) x Noggin rows
Nogging LM = Nogging count x Spacing x 0.90
Studs are placed at regular intervals plus one at each end. Additional studs are needed for door and window openings (king studs on each side) and at wall corners (3 studs per external corner for a nailing surface). The triple plate calculation (bottom plate plus double top plate) is standard for load-bearing and external walls in Australian residential construction. Noggings brace the studs between floors and provide nailing surfaces for sheet linings. The 0.90 factor on nogging lineal metres accounts for the gap between stud faces being slightly less than the full stud spacing.
3 Worked examples
⚠️ Illustrative example only — not clinical or professional instruction.
Studs from spacing: ceiling(6000/450) + 1 = ceiling(13.33) + 1 = 14 + 1 = 15 | Extra: 1 opening x 2 + 2 corners = 4 | Total studs: 19 | Stud length: 2.7 - 0.09 = 2.61m | Plates: 6.0 x 3 = 18.0 lm | Noggings: (15-1) x 1 = 14 pieces | Nogging LM: 14 x 0.45 x 0.90 = 5.67 lmStuds: ceiling(12000/600) + 1 = 20 + 1 = 21 | Extra: 0 + 2 = 2 | Total: 23 studs | Stud length: 2.4 - 0.09 = 2.31m | Plates: 12.0 x 3 = 36.0 lm | Noggings: (21-1) x 1 = 20 pieces | Nogging LM: 20 x 0.60 x 0.90 = 10.8 lmStuds: ceiling(240in/16in) + 1 = 15 + 1 = 16 | Extra: 2 x 2 + 2 = 6 | Total: 22 studs | Stud length: 9ft - (3.5in x 3 plates)/12 = 9ft - 0.875ft = 8.125ft (use 8ft precut) | Plates: 20 x 3 = 60 lm ft4 Sanity check
5 Common errors
| Error | Cause | Consequence | Fix |
|---|---|---|---|
| Not adding the end stud to the stud count | Dividing wall length by spacing without adding 1 for the end stud | One stud short on every wall -- the far end of each wall has no stud | Always add 1 to the result of (wall length / spacing) for the end stud: studs = ceiling(length/spacing) + 1. Check: a 900mm wall at 450mm spacing has 3 studs (at 0, 450, 900mm). |
| Ordering studs at wall height without deducting plate thicknesses | Ordering 2.7m studs for a 2.7m ceiling height wall | Studs too long -- every stud must be cut down on site, wasting time and creating excess timber offcuts | Stud length = Ceiling height - (Number of plates x 45mm). For a standard triple-plate wall at 2.7m ceiling: stud = 2.7 - 0.090 = 2.610m. Order 2.7m lengths and cut to 2.61m, or source precut studs at the correct length. |
| Using 600mm spacing for external walls or walls to receive tiling | Not checking substrate deflection requirements for tiles or structural requirements for external walls | Plasterboard or tile substrate flexes at mid-span between 600mm studs -- tile cracking and grout failure, or external wall racking capacity inadequate | All external walls and any wall that will receive ceramic or stone tiling must use 450mm stud spacing. 600mm spacing is only appropriate for internal non-load-bearing partitions with plasterboard lining where no tiles will be applied. |
| Not allowing for double top plate on load-bearing walls | Using single top plate everywhere to save timber | Load-bearing walls without double top plate may not comply with AS 1684 structural requirements | Load-bearing walls and walls that support roof loads require a double top plate under AS 1684. The double plate provides a continuous nailing and load transfer surface. Confirm which walls are load-bearing with the structural engineer. |
6 Reference & regulatory links
7 Professional workflow
Common tools used alongside this one: